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Code source de LifeType 1.2.4 |
1 <?php 2 // 3 // +----------------------------------------------------------------------+ 4 // | PHP Version 4 | 5 // +----------------------------------------------------------------------+ 6 // | Copyright (c) 1997-2003 The PHP Group | 7 // +----------------------------------------------------------------------+ 8 // | This source file is subject to version 2.0 of the PHP license, | 9 // | that is bundled with this package in the file LICENSE, and is | 10 // | available at through the world-wide-web at | 11 // | http://www.php.net/license/2_02.txt. | 12 // | If you did not receive a copy of the PHP license and are unable to | 13 // | obtain it through the world-wide-web, please send a note to | 14 // | license@php.net so we can mail you a copy immediately. | 15 // +----------------------------------------------------------------------+ 16 // | Author: Allan Kent <allan@lodestone.co.za> | 17 // +----------------------------------------------------------------------+ 18 // 19 // $Id: Human.php,v 1.3 2003/01/04 11:54:54 mj Exp $ 20 // 21 22 /** 23 * \ingroup Data 24 * 25 * Class to convert date strings between Gregorian and Human calendar formats. 26 * The Human Calendar format has been proposed by Scott Flansburg and can be 27 * explained as follows: 28 * The year is made up of 13 months 29 * Each month has 28 days 30 * Counting of months starts from 0 (zero) so the months will run from 0 to 12 31 * New Years day (00) is a monthless day 32 * Note: Leap Years are not yet accounted for in the Human Calendar system 33 * 34 * @since PHP 4.0.4 35 * @author Allan Kent <allan@lodestone.co.za> 36 */ 37 class Date_Human 38 { 39 40 /** 41 * Returns an associative array containing the converted date information 42 * in 'Human Calendar' format. 43 * 44 * @param int day in DD format, default current local day 45 * @param int month in MM format, default current local month 46 * @param int year in CCYY format, default to current local year 47 * 48 * @access public 49 * 50 * @return associative array( 51 * hdom, // Human Day Of Month, starting at 1 52 * hdow, // Human Day Of Week, starting at 1 53 * hwom, // Human Week of Month, starting at 1 54 * hwoy, // Human Week of Year, starting at 1 55 * hmoy, // Human Month of Year, starting at 0 56 * ) 57 * 58 * If the day is New Years Day, the function will return 59 * "hdom" => 0 60 * "hdow" => 0 61 * "hwom" => 0 62 * "hwoy" => 0 63 * "hmoy" => -1 64 * Since 0 is a valid month number under the Human Calendar, I have left 65 * the month as -1 for New Years Day. 66 */ 67 function gregorianToHuman($day=0, $month=0, $year=0) 68 { 69 /** 70 * Check to see if any of the arguments are empty 71 * If they are then populate the $dateinfo array 72 * Then check to see which arguments are empty and fill 73 * those with the current date info 74 */ 75 if ((empty($day) || (empty($month)) || empty($year))) { 76 $dateinfo = getdate(time()); 77 } 78 if (empty($day)) { 79 $day = $dateinfo["mday"]; 80 } 81 if (empty($month)) { 82 $month = $dateinfo["mon"]; 83 } 84 if (empty($year)) { 85 $year = $dateinfo["year"]; 86 } 87 /** 88 * We need to know how many days into the year we are 89 */ 90 $dateinfo = getdate(mktime(0, 0, 0, $month, $day, $year)); 91 $dayofyear = $dateinfo["yday"]; 92 /** 93 * Human Calendar starts at 0 for months and the first day of the year 94 * is designated 00, so we need to start our day of the year at 0 for 95 * these calculations. 96 * Also, the day of the month is calculated with a modulus of 28. 97 * Because a day is 28 days, the last day of the month would have a 98 * remainder of 0 and not 28 as it should be. Decrementing $dayofyear 99 * gets around this. 100 */ 101 $dayofyear--; 102 /** 103 * 28 days in a month... 104 */ 105 $humanMonthOfYear = floor($dayofyear / 28); 106 /** 107 * If we are in the first month then the day of the month is $dayofyear 108 * else we need to find the modulus of 28. 109 */ 110 if ($humanMonthOfYear == 0) { 111 $humanDayOfMonth = $dayofyear; 112 } else { 113 $humanDayOfMonth = ($dayofyear) % 28; 114 } 115 /** 116 * Day of the week is modulus 7 117 */ 118 $humanDayOfWeek = $dayofyear % 7; 119 /** 120 * We can now increment $dayofyear back to it's correct value for 121 * the remainder of the calculations 122 */ 123 $dayofyear++; 124 /** 125 * $humanDayOfMonth needs to be incremented now - recall that we fudged 126 * it a bit by decrementing $dayofyear earlier 127 * Same goes for $humanDayOfWeek 128 */ 129 $humanDayOfMonth++; 130 $humanDayOfWeek++; 131 /** 132 * Week of the month is day of the month divided by 7, rounded up 133 * Same for week of the year, but use $dayofyear instead $humanDayOfMonth 134 */ 135 $humanWeekOfMonth = ceil($humanDayOfMonth / 7); 136 $humanWeekOfYear = ceil($dayofyear / 7); 137 /** 138 * Return an associative array of the values 139 */ 140 return array( 141 "hdom" => $humanDayOfMonth, 142 "hdow" => $humanDayOfWeek, 143 "hwom" => $humanWeekOfMonth, 144 "hwoy" => $humanWeekOfYear, 145 "hmoy" => $humanMonthOfYear ); 146 } 147 148 /** 149 * Returns unix timestamp for a given Human Calendar date 150 * 151 * @param int day in DD format 152 * @param int month in MM format 153 * @param int year in CCYY format, default to current local year 154 * 155 * @access public 156 * 157 * @return int unix timestamp of date 158 */ 159 function HumanToGregorian($day, $month, $year=0) 160 { 161 /** 162 * Check to see if the year has been passed through. 163 * If not get current year 164 */ 165 if (empty($year)) { 166 $dateinfo = getdate(time()); 167 $year = $dateinfo["year"]; 168 } 169 /** 170 * We need to get the day of the year that we are currently at so that 171 * we can work out the Gregorian Month and day 172 */ 173 $DayOfYear = $month * 28; 174 $DayOfYear += $day; 175 /** 176 * Human Calendar starts at 0, so we need to increment $DayOfYear 177 * to take into account the day 00 178 */ 179 $DayOfYear++; 180 /** 181 * the mktime() function will correctly calculate the date for out of 182 * range values, so putting $DayOfYear instead of the day of the month 183 * will work fine. 184 */ 185 $GregorianTimeStamp = mktime(0, 0, 0, 1, $DayOfYear, $year); 186 return $GregorianTimeStamp; 187 } 188 189 } 190 ?>
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Généré le : Mon Nov 26 21:04:15 2007 | par Balluche grâce à PHPXref 0.7 |
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